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What is Dimensional Formula of Specific heat capacity ?

Specific heat capacity is defined as the quantity of heat required to increase the temperature of a unit mass of fluid by one temperature unit.

Mathematically,
Specific heat capacity = Q /m Θ

Where Q= Heat, m = mass  and Θ = Temperature

Dimensional formula of Heat(Q) = M1L2T-2
Dimensional formula of mass = M1L0T0
Dimensional formula of Temperature(Θ) = M0L0T0K1

Putting these values in above equation we get,
Dimensional formula of Specific Heat Capacity = M0L2T-2K-1
SI unit of Specific Heat Capacity is Joule kg-1 K-1

posted in Dimensional Formulae | 1 Comment

What is the formula for acceleration of a body rolling down a smooth inclined plane?

Consider a body of mass (M) and radius (R) rolling down (without slipping) a smooth inclined plane making an angle of inclination (Θ). When a body rolls down its Potential Energy ( resting at the top of inclined plane) is converted into the Kinetic energy of translation as well as rotation. As we know that body is rolling down a smooth inclined plane this means there will be no loss of energy due to friction. So the loss in Potential Energy is same as gain in kinetic energy.

Loss in potential Energy = Gain in kinetic energy

Mgh = ½ (M v2) + ½ (I ω 2)

formula for acceleration of body rolling down a smooth inclined plane

From the above fig we know that h = ℓ sin Θ, substituting this in the above equation we get,
Mg ℓ sin Θ = ½ (M v2) + ½ (I ω 2)
Mg ℓ sin Θ = ½ (M v2) + ½ (M K2 .(v2 / R 2) )
Where K = radius of gyration, ω = v/R and I = M K2

Mv2 / 2 (1 + (K2 / R2)) = Mg ℓ sin Θ

v2 = 2 g ℓ sin Θ / (1 + (K2 / R2)) but v2 = 2aℓ

 

So Formula for acceleration of a body rolling down a smooth inclined plane,

a = g sin Θ / (1 + (K2 / R2))

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What is the Law of conservation of angular momentum?

Law of conservation of angular momentum is stated as “If the total external torque acting on a body is zero, the total angular momentum of that body remains constant or conserved”. This means that the angular momentum of that body remains same in absence of external torque.

According to the Law of conservation of angular momentum

         Angular momentum = I1ω1 = l2ω2= constant

I1 and ω1 are the initial moment of inertia and angular velocity of a rotating body

I2 and ω2 are new moment of inertia and angular velocity of the body

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What is the expression for Angular momentum of a Rigid body rotating about an axis?

A rigid body rotates about a fixed axis. The rigid body consists of a large number of particles.
Let m1, m2, m3 etc., be the masses of the particles situated at distances r1, r2, r3 , … etc., from the fixed axis. All the particles rotate with the same angular velocity, but with different linear velocities depending on the values of ‘r’.
The angular momentum of a rigid body (L) = m1 r12ωm2 r22ω…
The angular momentum of a rigid body (L) = (m1 r12 + m2 r22….) ω

The angular momentum of a rigid body (L) = Σ mr2ω …………………(1)

But, Σmr2 = moment of inertia of the rigid body = I

Therefore,

Angular momentum of a Rigid body = I × ω……putting value of I in (1)

Angular momentum of a Rigid body = moment of inertia of the rigid body ( I) x × angular velocity (ω)

The S.I. unit for angular momentum is kgm2rad/s or kgm3/s

 

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What is the formula for Angular momentum?

The moment of linear momentum is known as angular momentum. In other words the rotational analog of linear momentum is known as angular momentum
Consider a particle of mass m at a distance r from the axis of rotation. When a particle is in rotational motion about an axis, it has both linear velocity ‘v’ and angular velocity ‘ω’.

Angular momentum of the particle = linear momentum x perpendicular distance between
the particle and the axis of rotation or radius (r)

We know that momentum = mass × velocity
Substituting the value of momentum in the above equation we get,
Angular momentum = m v × r
we know that relation between Linear velocity and Angular velocity is defined as
Linear velocity (v) = Radius (r) x Angular velocity (ω)

Substituting the values we get
Angular momentum = m × (r. ω) × r
Therefore, the formula for Angular momentum is given as,
Angular momentum = mr2ω
The S.I. unit for angular momentum is kgm2s-1

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